Exploring 2018 Aime Prob 5
Exploring 2018 Aime Prob 5 reveals several interesting facts.
- In this
- The
- Actually, k=2, 11, 22 is the full set of possible k values. I skipped over k=2 when I first did this
- AOPS link with solution: https://www.artofproblemsolving.com/wiki/index.php?title=2001_AIME_I_Problems/Problem_5.
- AIME problem
In-Depth Information on 2018 Aime Prob 5
To tidy up this last detail, we need to show that the solutions we find after stripping away the logs do not force any of the log( ) ... QUESTION from Long Le: Why can we equate the fractional part of the numbers? I mean, couldn't you just add the integral to ... If we define the angles, in degrees, Θ = Angle(z), and α = Angle(z^120) = 120•Θ {De Moivre's Theorem} ß = Angle(z^720) = 720•Θ ... Problem
STEMerch @Twitter: https://twitter.com/merch_ste SUb to @NPCooking69 Competitive Playlist: ...
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